V to I Converters (Voltage to Current Converter) multiple choice questions

 V to I Converters (Voltage to Current Converter)

1. Find the voltage drop across the zener diode in the zener diode tester from the given specifications: I_Zk=1mA, V_Z =6.2v, input voltage= 1.2v, output voltage =3.2v and resistance in series with meter =150Ω.
a) 6.2mA
b) 8mA
c) 21.33mA
d) Cannot be determine
Answer: 6.2mA
2. For voltage to current converter with grounded load, establish a relation between the non-inverting input terminals and load current
a) V₁ = [V_in+V_o-(I_L×R)] /2
b) V₁ = [V_in-V_o-(I_L×R)] /2
c) V₁ = [V_in+V_o-I_L+R] /2
d) V₁ = [V_in+V_o+(I_L×R)] /2
Answer: V₁ = [V_in+V_o-(I_L×R)] /2
3. Voltage to current converter is also called as
a) Current series positive feedback amplifier
b) Voltage series negative feedback amplifier
c) Current series negative feedback amplifier
d) Voltage series positive feedback amplifier
Answer: Current series negative feedback amplifier
4. The maximum current through the load in all application that uses voltage to current converter with floating is
a) 100mA
b) 75mA
c) 25mA
d) 50mA
Answer: 25mA
5. Which of the following application uses voltage to current converter?
a) Low voltage dc and ac voltmeter
b) Diode match finding
c) Light emitting diode
d) All of the mentioned
Answer: All of the mentioned
6. Which among the following is preferred to display device in digital application?
a) Matched zener diode
b) Matched LEDs
c) Matched rectifier diode
d) All of the mentioned
Answer: Matched LEDs
7. The op-amp in low voltage DC voltmeter cannot be nullified due to
a) D’Arsonaval meter movement
b) Offset voltage compensating network
c) Selection of switch
d) Gain of amplifier
Answer: D’Arsonaval meter movement
8. What is the maximum input voltage that has to be selected to calibrate a dc voltmeter with a full scale voltage range of 1-13v.
a) ≤ ±14v
b) ≥ ±13v
c) ≤ ±15v
d) = ±14v
Answer: ≤ ±14v
9. Determine the full scale range for the input voltage if the resistance in series with meters are 1kΩ, 2kΩ, 47kΩ and full scale meter movement is 1mA in low voltage AC voltmeter?
a) 1.0 to 7.48 V_rms
b) 1.1 to 7.48 V_rms
c) 1.2 to 7.48 V_rms
d) 1.3 to 7.48 V_rms
Answer: 1.1 to 7.48 V_rms
10. Find the gain of the voltage to current converter with grounded load?
a) 2
b) 1
c) ∞
d) 0
Answer: 2
11. Higher input voltage can be measured in low voltage DC voltmeter using
a) Smaller resistance value
b) Higher resistance value
c) Random resistance value
d) All of the mentioned
Answer: Higher resistance value
12. A diode match finder circuit has input voltage of 2.6v and output voltage is 5.78v. Calculate the voltage drop across diode 1N4735
a) 2.22v
b) 8.38v
c) 3.18v
d) 15.02v
Answer: 3.18v
13. How to modify a low voltage DC voltmeter to low voltage ac voltmeter
a) Add a full wave rectifier in the feedback loop
b) Add a half wave rectifier in the feedback loop
b) Add a square wave rectifier in the feedback loop
b) Add a sine wave rectifier in the feedback loop
Answer: Add a full wave rectifier in the feedback loop

Current to Voltage Converter

1. Which cell can be used instead of a photocell to obtain active transducer in photosensitive devices?
a) Photovoltaic cell
b) Photo diode
c) Photo sensor
d) All of the mentioned
Answer: Photovoltaic cell
2. The output current equation for MC1408 digital to analog converter would be
a) I_o= -(V_ref/R₁)×[(D₇/2)+(D₆/4)+(D₅/8)+(D₄/16)+(D₃/32)+(D₂/64)+(D₁/128)+(D₀/256)].
b) I_o= (V_ref/2R₁)×[(D₇/2)+(D₆/4)+(D₅/8)+(D₄/16)+(D₃/32)+(D₂/64)+(D₁/128)+(D₀/256)].
c) I_o= (V_ref/R₁)×[(D₇/2)+(D₆/4)+(D₅/8)+(D₄/16)+(D₃/32)+(D₂/64)+(D₁/128)+(D₀/256)].
d) I_o= -(V_ref/2R₁)×[(D₇/2)+(D₆/4)+(D₅/8)+(D₄/16)+(D₃/32)+(D₂/64)+(D₁/128)+(D₀/256)].
Answer: I_o= (V_ref/R₁)×[(D₇/2)+(D₆/4)+(D₅/8)+(D₄/16)+(D₃/32)+(D₂/64)+(D₁/128)+(D₀/256)].
3. The current to voltage converter photosensitive device can be used as
a) Light intensity meter
b) Light radiating meter
c) Light deposition meter
d) None of the mentioned
Answer: Light intensity meter
4. Determine the maximum value of output current of the DAC in MC1408?
a) 0.773×(V_ref/R₁)
b) 0.448×(V_ref/R₁)
c) 0.996×(V_ref/R₁)
d) 0.224×(V_ref/R₁)
Answer: 0.996×(V_ref/R₁)
5. For a full wave rectification, in a low voltage ac voltmeter, the meter current can be expressed as
a) I_o = (1.9×V_in)/R₁
b) I_o = (3.9×V_in)/R₁
c) I_o = (0.9×V_in)/R₁
d) I_o = (2.9×V_in)/R₁
Answer: I_o = (0.9×V_in)/R₁
6. If the input applied to DAC using current to voltage converter is 10110100, determine the reference voltage (Assume I_o= 2mA and R₁=1.2kΩ)
a) 53.1v
b) 3.41v
c) 9.21v
d) 67.34v
Answer: 3.41v